reversing an integer with overflow handled
// Java program to reverse digits // of a number public class GFG { static int reversDigits(int num) { int rev = 0 ; while(num != 0){ int rem = num % 10 ; num /= 10 ; if(rev > Integer.MAX_VALUE/10 || rev == Integer.MAX_VALUE/10 && rem > 7){ return 0 ; } if(rev < Integer.MIN_VALUE/10 || rev == Integer.MIN_VALUE/10 && rem < -8){ return 0 ; } rev = rev*10 + rem ; } return rev ; } // Driver code public static void main (String[] args) { int num = 12345; System.out.println("Reverse of no. is " + reversDigits(num) ); num = 1000000045; System.out.println("Reverse of no. is " + reversDigits(num) ); } } // This code is contributed by jana_sayantan.
Source: www.geeksforgeeks.org