c++ evaluate expression
#include "tinyexpr.h" #include <stdio.h> int main() { double answer = te_interp("3*2+4*1+(4+9)*6", 0); printf("Answer is %f\n", answer); return 0; }
Source: stackoverflow.com
#include "tinyexpr.h" #include <stdio.h> int main() { double answer = te_interp("3*2+4*1+(4+9)*6", 0); printf("Answer is %f\n", answer); return 0; }