该函数使用当前舍入模式舍入给定值,并返回long int类型的值。
假设数字是“ x”。语法为:
long int lrint(data_type x);
x :可以是float,double或long double的值。
它返回x的舍入值,并且该值的返回类型为long int。
让我们看一个简单的例子。
#include <iostream> #include<math.h> #include <cfenv> using namespace std; int main() { float r; int str; cout<<"Enter the value which you want to round :"; std::cin >> r ; cout<<'\n'; cout<<"Name of the methods are :"<<'\n'<<"1. Rounding downwards"<<'\n'<<"2. Rounding upwards"<<'\n'<<"3. Rounding towards zero"<<'\n'<<"4. Rounding to the nearest"<<'\n'; cout<<"Enter the number of rounding method :"; cin>>str; cout<<'\n'; switch(str) { case 1: fesetround(FE_DOWNWARD); cout<<"Rounding downwards,value is :"<<lrint(r)<<'\n'; break; case 2: fesetround(FE_UPWARD); cout<<"Rounding upwards,value is :"<<lrint(r)<<'\n'; break; case 3: fesetround(FE_TOWARDZERO); cout<<"Rounding towards zero,value is :"<<lrint(r)<<'\n'; break; case 4: fesetround(FE_TONEAREST); cout<<"Rounding to nearest,value is :"<<lrint(r)<<'\n'; break; default: cout<<"wrong method"; } return 0; }
输出:
Enter the value which you want to round : 7.8 Name of the methods are : 1. Rounding downwards 2. Rounding upwards 3. Rounding towards zero 4. Rounding to the nearest Enter the number of rounding method : 1 Rounding downwards,value is :7
祝学习愉快!(内容编辑有误?请选中要编辑内容 -> 右键 -> 修改 -> 提交!)